3 years ago

Find the slope intercept form.

1 answer:

3 0

Answer:

y = 3x + 9

Step-by-step explanation:

y = 3x + 6

Parallel slope = 3

(-2, 3)

Slope-intercept:

y - y1 = m(x - x1)

y - 3 = 3(x + 2)

y - 3 = 3x + 6

y = 3x + 9

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The value of the expression $\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$ is $2xy\sqrt{y} + 2xy^2\sqrt{x}$

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

$\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$

Expand the radicands

$\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y$

Evaluate the square roots

$xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y$

Add the like terms

$2xy\sqrt{y} + 2xy^2\sqrt{x}$

Hence, the value of the expression $\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y$ is $2xy\sqrt{y} + 2xy^2\sqrt{x}$