Answer:
Minimum length of rope needed to span the sides of the prism is 10 units.
Step-by-step explanation:
Let us draw a perpendicular from apex to base BC,Let it be AD since ΔABC is isosceles triangle, that perpendicular will touch mid of base. That is BD=DC=
=3
Now we know the angle m∠ABC as 53.13°.
From ΔADC, 
≈10
Hence minimum length of rope needed to span the sides of prism is 10 units.
Answer:
Blanks top to bottom: 6^2, 36, 9, 108, 101
Step-by-step explanation:
Use PEMDAS which stands for parentheses, exponents, multiplication, division, addition, and subtraction. Listed in this specific order, you must look and solve for each one first, starting with parentheses.
4.
12 × ((4+2)^2/4) - 7
Solve for inside of parentheses first:
12 × ((6)^2/4) - 7
12 × (36/4) - 7
12 × 9 - 7
108 - 7
101
Since the square is on a quadrant plane and it is a square, the fact that the lines cross in the center and start and stop in the corners allows you to tell that they are perpendicular.
So answer one is (B, D) 2 is (0, C) 3 is: 1
Answer: The answer to a system of equations is the point(s) of intersection of the equation involved.
When you have more than one equation with more than one variable, you have a system of equation. The solution(s) is the set of values for each variable that satisfy the equations. This means that the inputting values make the equations true.
So the slope of the first line is 4/3. If this line is perpendicular, then you have to flip it and switch the sign (flip it n switch it (how I remember it)). So the slope of the new line is -3/4.
Then you have to plug in the point you're given and the new slope. Use y=mx+b format.
-1=-3/4*-4+b
Then solve for b.
-3/4*-4 is 3.
-1=3+b
Subtract 3 from each side.
-4=b.
So now you have the y-intercept and slope. All you have to do is plug it in.
y=-3/4x + -4 or y=-3/4 - 4
There's your answer!
