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vivado [14]
3 years ago
10

A-5/a divided by 4/a

Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer:

\frac{a-5}{4}

Step-by-step explanation:

the given equation is

\frac{a-5}{a} /\frac{4}{a}

from the multiplication rules we know that

\frac{a}{b}/\frac{c}{d}=\frac{a}{b}*\frac{d}{c}

so for the given equation changing the sidn of division to multiplication

the equation becomes

\frac{a-5}{a} * \frac{a}{4}

a cancels out from both numerator and denominator

so it becomes

\frac{a-5}{4}

which is the answer

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Zepler [3.9K]

Answer: The answer is -9

Step-by-step explanation:

7z<-28= -9

Because we take the -28 and add 19 because that's the common denominator and we come up with -9

6 0
3 years ago
Let G be a connnectde graph with n vertices and m edges. supposed also that m = n. prove that G contains exactly one cycle
ElenaW [278]

Answer:

Contradiction

Step-by-step explanation:

Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.

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tensa zangetsu [6.8K]
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The answer is 50 mins.
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Answer:

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Step-by-step explanation:

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