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3 years ago

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the Dimensions of Prokaryotic Cells and their Constituents Escherichia coli cells are about 2 mm (microns) long and 0.8 mm in di

ameter. (Section 1.5) a. How many E. coli cells laid end to end would fit across the diameter of a pinhead? (Assume a pinhead diameter of 0.5 mm.)

1 answer:

torisob [31]3 years ago

4 0

Answer:

Try Photomath !

Step-by-step explanation:

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Divide <br> (6-q+8q^3-4q^2)/(2q-2)

mestny [16]

Answer:

Step-by-step explanation:

4q2 + 2q + 3

(2q - 2) l _ 8q3 - 4q2 - q + 6

8q3 - 8q2

_ 4q2 - q

4q2 - 4q

_ 3q + 6

6q + 6

-3q (remainder)

4q2 + 2q + 3 -3q / (2q - 2)

hope this helps

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3 years ago

How to solve 6x+5x-4=2x-8

solniwko [45]

6x+5x-4=2x-8~~~First we simplify(add 6x and 5x)
11x-4=2x-8~~~Now add 4 to both sides
+4 +4
11x=2x-4~~~~Remove 2x from both sides now.
-2x -2x
9x=-4~~~~Now divide by 9x
÷9x ÷9x

x= -4/9

6 0

3 years ago

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Solve the equation x^3+2x^2-5x-6=0

Bezzdna [24]

Solution is X=-1 , 2, -3

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3 years ago

Find the diameter and radius of a circle with a circumference of 65.98 Please help

viva [34]

Answer:

21 and 10.5 respectively

Step-by-step explanation:

Remember circumference of a circle is given as;

C= 2×π×r; r is raduis

r = C / 2×π

=65.98/(2×3.142)= 10.50

D= 2× r = 2× 10.50= 21.0( D represent diameter)

Note π = 3.142 a known constant

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3 years ago

The length of the subway is 850 miles. If .15 inch represents 45 miles, what is the length of the subway on the map?

Scilla [17]

Answer:

The length of the subway on the map is $2.83\ inches$

Step-by-step explanation:

we know that

The scale on the map is equal to the length of the subway on the map divided by the length of the subway in the actual

so

Let

z------> the scale on the map

x------> the length of the subway on the map

y------> the length of the subway in the actual

$z=\frac{x}{y}$

In this problem we have

$z=\frac{0.15}{45}\frac{inches}{miles}$

$y=850\ miles$

substitute and solve for x

$\frac{0.15}{45}=\frac{x}{850}$

$x=850*\frac{0.15}{45}=2.83\ inches$

6 0

4 years ago

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