3 years ago

Divide (6-q+8q^3-4q^2)/(2q-2)

Mathematics

1 answer:

mestny [16]3 years ago

4 0

Answer:

Step-by-step explanation:

4q2 + 2q + 3

(2q - 2) l _ 8q3 - 4q2 - q + 6

8q3 - 8q2

_ 4q2 - q

4q2 - 4q

_ 3q + 6

6q + 6

-3q (remainder)

4q2 + 2q + 3 -3q / (2q - 2)

hope this helps

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$\boxed {\boxed {\sf B. \ \frac{8}{13} }}$

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