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user100 [1]
3 years ago
12

a parking garage has 6 levels. Each level has 15 row. Each row has the same number of parking spaces. there are 2,250 parking sp

aces in all. How many parking spaces are in each row? Write an equation of equations to show your work.
Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0
To start with, we know there’s a definite amount of parking spaces in all(2,250) and we also know each level(6 in all) had 15 rows of parking spaces.

Equation

A = Parking spots per row


A = 2,250 Divided by(6 levels times 15 rows)

A= 2,250 Divided by 90


A = 25

The correct answer is 25 parking spots per row

To check this answer we can do

25 spots per row, Times 15 rows per level, Times the total amount of levels (6)

= the total amount of parking spots

25*15*6= 2,250

True


This confirms this answer as correct. Hope this helps.
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3 years ago
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jonny [76]

Answer:

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3 years ago
Read 2 more answers
Which of the following is not a true bi-conditional statement?
mrs_skeptik [129]
<h3>Answer: Choice B) </h3>

Jane goes to the beach if and only if it is a sunny day.

========================================================

Reason:

A regular conditional statement is in the form "If P, then Q" where P and Q are placeholders for other statements.

For example, we can replace "P" with "it rains" and replace "Q" with "the grass gets wet". This means "If P, then Q" becomes "If it rains, then the grass gets wet".

It's hopefully clear that the example above is a one way street. It points in only one direction. The act of raining leads directly to the grass being wet. However, we cannot go in reverse. If we see the grass is wet, it doesn't mean it rained. Perhaps someone turned on a hose or sprinkler system. P leads to Q, but Q does not lead to P.

In short, all of what is mentioned so far is considered a regular conditional statement. So far we haven't addressed bi-conditional statements.

----------------

Bi-conditional statements are conditionals that work in reverse.

An example would be "If a figure is a square, then it has 4 congruent sides and 4 right angles". That conditional statement works in reverse. Therefore "If a figure has 4 congruent sides and 4 right angles, then the figure is a square" is also true simply by what it means to be a square.

So the format "If P, then Q" can be reversed to "If Q, then P" to have an equivalently true statement. The common practice is to use "if and only if" to help shorten things.

We would have the template "P if and only if  Q" which is the same as "Q if and only if P". The order doesn't matter since we can reverse things just fine.

Often you'll find bi-conditional statements when it comes to definitions. The term "weekend" literally means the day is either Saturday or Sunday, which is why choice C is another bi-conditional. A very similar situation applies to choice D as well.

--------------------

We've found that choices A, C and D are bi-conditional statements. They can be ruled out. We're left with choice B.

This is not a bi-conditional. Why not? It's assumed that Jane would go to the beach on a sunny day, but perhaps she enjoys the beach just fine on cloudy days. There's also the fact she could be doing other things on sunny days. The presence of the sun doesn't automatically mean the beach. If you said "It gets warm if and only if it's a sunny day", then I think this is more in line with a bi-conditional.

This is why <u>choice B</u> is the final answer.

6 0
2 years ago
of 30 students , 1/3 play sports. of those who play sports , 2/5 play soccor. how many students play soccor.
Mekhanik [1.2K]

Answer:

4 play soccer.

Step-by-step explanation:

(1/3 * 2/5) * 30

(2/15) * 30

(4/30) * 30

4

6 0
3 years ago
A solid right​ (noncircular) cylinder has its base R in the​ xy-plane and is bounded above by the paraboloid zequalsx2plusy2. Th
Aleonysh [2.5K]

Answer:

a. V = 4/3

b. See attachment

Step-by-step explanation:

a.

Given

Z = x² + y²

V = ∫ ∫ (x² + y²) dxdy {0,1}{0,y} + ∫ ∫ (x² + y²) dxdy {0,1}{x,2-x}

V = ∫ ∫ (x² + y²) dxdy {0,1}{x,2-x}

Integrate with respect to y

V = ∫ x²y+ y³/3 dx {0,1}{x,2-x}

V = ∫ x²(2-x) + (2-x)³/3 - x²(2) - (2)³/3 dx {0,1}

V = ∫ 2x² -7x³/3 + (2-x)³/3 dx {0,1}

V = 2x³/3 - 7x⁴/12 + (2-x)⁴/12 {0,1}

V = (⅔ - 7/4 + 2/12) - (0-0+16/12)

V = 4/3

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3 years ago
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