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tamaranim1 [39]
3 years ago
15

Thirty-three percent of all students at a high school like beef stew. Put of 300 students, 40 are selected randomly and asked wh

ether they liked beef stew. If liking beef stew is a success, what is the probability of a failure for this binomial experiment?
A) 0.33
B) 0.40
C) 0.57
D) 0.67
Mathematics
2 answers:
Elan Coil [88]3 years ago
7 0
Thirty-three percent of all students at a high school like beef stew. Put of three hundred students, forty are selected randomly and asked whether they liked beef stew. If liking beef stew is a success, the probability of a failure for this binomial experiment would be 0.67. The answer would be letter D.
Leona [35]3 years ago
6 0

Answer:

the answer is D 0.67

Step-by-step explanation:

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Zoologists are studying two newly discovered species of insects in a previously unexplored section of rain forest. They estimate
salantis [7]
The population Pa of insect A after t years is given by the equation 
     Pa = 1.3(1-0.038)^t 
while the population Pb of insect B after t years is 
     Pb = 2.1(1-0.046)^t

We equate the above expressions to find the number of years t it will take the two populations to be equal: 
     Pa = Pb
     1.3(1-0.038)^t  = 2.1(1-0.046)^t
     1.3(0.962)^t  = 2.1(0.954)^t
These are the equations that can be used to determine how long it will be before the populations of the two species are equal.

We can now solve for t:
     (0.962)^t / (0.954)^t = 2.1/1.3
     (0.962/0.954)^t = 2.1/1.3
After taking the log of both sides of our equation, number of years t is
     t = log (2.1/1.3) / log (0.962/0.954)
     t = 57 years
Therefore, it will take 57 years for the population of insect A to equal the population of insect B.
8 0
3 years ago
Read 2 more answers
Help me please 2 minutes for class to start
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From c=b-5

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3 years ago
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pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
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