At this weekend’s football game, 15 out of the first 50 people who entered the field were not wearing hats. If this sample is re
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For this case we propose a system of equations. We have to:
x: Let the variable that represents the number of dimes
y: Let the variable that represents the number of quaters
We know that:
One dime equals 10 cents, $0.10
A quater equals 0.25 cents, $0.25
According to the statement we have:
We multiply the first equation by -0.10:
We have the following equivalent system:
We add the equations:
Approximately 3 quater coins
And two dimes
Answer:
3 quater
2 dimes
we are given that ,
The combined area of two squares is 17 square meters.
Area of square=
Let the side length of smaller square be x
The size of the larger Square are four times as long as the size of the smaller square
So Area of larger square=
The combined Area is 17 square meter.
Hence the smaller square has the side length=
So the larger square has side length=