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Lady bird [3.3K]
3 years ago
11

a country club offers membership to it's customers. there is a one-time application fee of $75 and the dues are $25 per month. w

rite an equation to represent the total cost of membership at this country club​
Mathematics
1 answer:
Lilit [14]3 years ago
3 0

Answer: 25x + 75

Step-by-step explanation:

The 25 is the monthly fee, x stands for the number of months and the 75 is the set fee

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Paul´s dog weighs 9.75 pounds more than Hailey´s dog. If Hailey´s dog weighs 12 pounds, how much does Paul´s dog weigh?
scoray [572]

Answer:

21.75 pounds

Step-by-step explanation:

 12.00 +  9.75= 21.75

8 0
3 years ago
Read 2 more answers
The diagonals of rectangle ABCD intersect at point E. If AE = 2x + 5, and BD = 5x + 2, what is AC?
Mkey [24]

<u>C. 42 units</u>

Step-by-step explanation:

I have attached a diagram to help you understand this problem. By looking at the diagram you can see that AE is half of BD, and that BD will be equal to AC. So we need to figure out the length of line BD to get AC.

To do this, you will multiply the length of AE by 2 and set it equal to BD.

2(2x+5)=5x+2

Then distribute, multiply what is in the parentheses by 2.

4x+10=5x+2\\\\

Subtract 4x from both sides.

10=1x+2

Subtract 2 from both sides.

8=1x

x = 8

Now that we have x, we can plug it into the equation to find BD.

5 * 8 + 2=42

BD is equal to 42 units, so we know...

<u><em>AC = 42 units</em></u>

4 0
3 years ago
A rare form of malignant tumor occurs in 11 children in a​ million, so its probability is 0.000011. Four cases of this tumor occ
Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

\lambda=r*t=0.000011*13,280=0.14608

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990

c) The probability of more than one case is:

P(k>1)=1-P(k\leq 1)=1-0.990=0.010

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0
3 years ago
Simplify three over five divided by negative four over nine..
gladu [14]
3/5 divided by -4/9
3/5 times the reciprical -9/4
-27/20=-1 7/20
3 0
3 years ago
What is the the union for the following sets.
BlackZzzverrR [31]

Answer:

  X ∪ Y = {0, 10, 100, 1000}

Step-by-step explanation:

Y is a subset of X, so the union of the two sets is the same as set X:

  {0, 10, 100, 1000}

7 0
3 years ago
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