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lorasvet [3.4K]
3 years ago
7

Find the value of XA: 2B: 4C: 6D: 8​

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Using the Pythagorean theorem:

x^2 + (x-2)^2 = (√20)^2

Simplify the right side:

x^2 + (x-2)^2 = 20

Subtract 20 from both sides:

x^2 + (x-2)^2 - 20 = 0

Factor:

(x-4)(x+2) = 0

Solve for each x:

x = 4 and x = -2

The side cant be a negative value, so the answer would be x = 4

The answer is B.

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3 years ago
Selma cannot remember her locker number! She knows that her locker number is prime, and that it is a factor of 435. What are all
tatuchka [14]

Answer:

Possible locker numbers for Selma are: 3, 5 and 29

Step-by-step explanation:

First of all, let us have a look at the definition of a prime number.

A <em>prime number</em> is a number which is divisible either by 1 or the number itself.

No other number divides the prime number other than 1 and the number itself.

Now, let us factorize the given number 435 and let us observe the what all possibilities are there.

435 = 3\times 145

Factorizing 145 further:

435 = 3\times 5\times 29

No further factors are possible.

Therefore 3, 5 and 29 are the prime factors of 435.

So, the answer is:

Possible locker numbers for Selma are: 3, 5 and 29

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What’s the question?
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2 years ago
Quadrilateral ABCD is inscribed in this circle.
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step-by-step explanation: this is the formular for finding a midpoint of a line.

  1. <u>midpoint=x1+y1?|/2 ,x2+y2/2</u>
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