Answer:
a) what is the probability that Neither will of these products launch ?
= 0.30
b) At least one product will be launched ?
= 0.70
Step-by-step explanation:
From the above question, we have the following information:
P(A) = 0.45
P(B) = 0.60
P(A ∩ B) = P(A and B) launching = 0.35
Step 1
We find the Probability that A or B will launch
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
a) what is the probability that Neither will of these products launch ?
1 - Probability ( A or B will launch)
= 1 - 0.70
= 0.30
b)At least one product will be launched?
This is equivalent to the probability that A or B will be launched
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
Answer:
D
Step-by-step explanation:
3+7=10 because three and seven are both in your equation so after adding 3 and 7 all you must do is add 5 to 10
Alright, lets get started.
Kendrick's Kennel has 2 spots for cats for every 7 spots for dogs.
Suppose spots for cats = 2x
So, spots for dogs will be = 7x
Total spots for cats and dogs will be = 
Total spots for cats and dogs will be = 
As per given in question, total spots for both cats and dogs are 144, so
Dividing 9 in both sides
x = 16
So, spots for cats = 
Spots for dogs = 
So, spots for dogs more than cats are = 
It means he has 80 more spots for dogs than cats. : Answer
Hope it will help :)
