Question

For a right circular cylinder, if the radius is tripled and the height is shrunk down to half its size, then what is the surface area if the original radius is 7 inches and the original height is 17 inches? Round your answer to the nearest hundredth.
A.
3,289.43 in.²
B.
3,298.43 in.²
C.
3,892.43 in.²
D.
3,982.43 in.²

Answer 1

The surface area of a cylinder that the radius tripled and it height is brought down to half is 3890.46 inches²

How to find the surface area of a cylinder?

Surface area of a cylinder = 2πr(r + h)

Therefore,

radius is tripled = 3(7) = 21 inches

height is shrunk half its size = 17 / 2 = 8.5 inches

Therefore,

surface area = 2 × 3.14 × 21 (21 + 8.5)

surface area = 131.88(29.5)

surface area = 3890.46 inches²

learn more on cylinder here: brainly.com/question/16551354

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