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dybincka [34]
3 years ago
13

What is the area of a triangle with a height of 13 cm and a base of a 10 cm?

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0
Area of a triangle is equal to 1/2 b(h) so since you already have the height and base, all you need to do is input it back into the equation:

\frac{1}{2} (10)(13)


Multiply 10 & 13 to equal 

\frac{1}{2} (130)

Then take half of 130 to get

A = 65 cm^{2}
natali 33 [55]3 years ago
7 0
Greetings!

The Formula for the Area of a Triangle is: A= \frac{bh}{2}

Input the values we already know:
A= \frac{10*13}{2}

Solve for A.
A= \frac{130}{2}

A= \frac{130}{2}

A=65

The Answer Is:
\left[\begin{array}{ccc}A=65\end{array}\right]

The Area of the Triangle is 65 cm²

Hope this helps.
-Benjamin
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Points J, K and L are collinear with J between L and K. If KJ = 2x-3, LJ= 4x-8, solve for x:
notsponge [240]

Your question is incomplete, here is the complete form.

Points J, K and L are collinear with J between L and K.  If KJ = 2x - 3, LK = 9x + 7 and LJ = 4x - 8,  solve for x:

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Step-by-step explanation:

∵ J, K, and L are collinear

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∵ J is between K and L

→ That means J divides LK into two segments KJ and LJ

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Step-by-step explanation:

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