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dybincka [34]
3 years ago
13

What is the area of a triangle with a height of 13 cm and a base of a 10 cm?

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0
Area of a triangle is equal to 1/2 b(h) so since you already have the height and base, all you need to do is input it back into the equation:

\frac{1}{2} (10)(13)


Multiply 10 & 13 to equal 

\frac{1}{2} (130)

Then take half of 130 to get

A = 65 cm^{2}
natali 33 [55]3 years ago
7 0
Greetings!

The Formula for the Area of a Triangle is: A= \frac{bh}{2}

Input the values we already know:
A= \frac{10*13}{2}

Solve for A.
A= \frac{130}{2}

A= \frac{130}{2}

A=65

The Answer Is:
\left[\begin{array}{ccc}A=65\end{array}\right]

The Area of the Triangle is 65 cm²

Hope this helps.
-Benjamin
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Step-by-step explanation:

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3 years ago
Which can't be lenght side of triangle
Luda [366]

Answer:

C. sides of 3, 4 and 7

can't form a triangle.

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Step-by-step explanation:

5 0
3 years ago
For what value of “a”are the graphs of 5y = -2x + 10 and 3y = aX- 15 parallel
Pie

Answer:

a = -6/5

Step-by-step explanation:

For the graphs to be parallel the graphs should have same slope(m)

So we rewrite both our equations in the slope-intercept form then compare the slope to find the value of a like this,

y=mx+b

This equation is the slope-intercept form we convert both our equations in this form firstly taking equation 1

5y=-2x+10\\\\y=\frac{-2x+10}{5} \\\\y=\frac{-2}{5}x+\frac{10}{5} \\\\y=\frac{-2}{5}x+2

so if we compare it with y = mx + b the coefficient of x is m and hence

m= -2/5 now solving for equation 2

3y=ax-15\\\\y=\frac{ax-15}{3} \\\\y=\frac{ax}{3}-\frac{15}{3}  \\\\y=\frac{a}{3}x-5\\\\

so here if we compare it with y = mx + b the coeffienct of x is a/3 so since parallel lines have same slope by the formula:

m_1=m_2

we equation both the slope to each other to find the value of a like this,

m_1=m_2\\\\\frac{-2}{5}=\frac{a}{3}\\\\-2(3)=a(5)\\\\-6=5a\\-6/5=a

so the value of a equals

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8 0
2 years ago
-xv-2v+14x+7x^2<br><br> Factor By grouping
RoseWind [281]
The answer to the question

3 0
3 years ago
Given rectangle QUAD, If DU = 5x - 4 and QP = 2x + 7, then find the length of DU.
ira [324]

Answer:

DU = 86

Step-by-step explanation:

Properties of a rectangle,

- Opposite sides are equal in measure.

- Diagonals of a rectangle are equal.

- Diagonals bisect each other.

In the given rectangle QUAD,

Diagonals AQ and DU bisect each other at P.

AQ = DU

2(QP) = DU [Since, AQ = 2(PQ)]

2(2x + 7) = 5x - 4

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5x - 4x = 14 + 4

x = 18

Since, DU = 5x - 4

DU = 5(18) - 4

     = 90 - 4

     = 86

Therefore, measure of DU = 86 units

3 0
2 years ago
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