3 years ago

Help me solve this problem in the photo, need help asap

1 answer:

7 0

$\dfrac{2x^2+7x-4}{2x^2-32}=\\
\dfrac{2x^2+8x-x-4}{2(x^2-16)}=\\
\dfrac{2x(x+4)-1(x+4)}{2(x-4)(x+4)}=\\
\dfrac{(2x-1)(x+4)}{2(x-4)(x+4)}=\\
\dfrac{2x-1}{2(x-4)}
$

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4 years ago

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