Question

Help me solve this problem in the photo, need help asap

Answer 1

$\dfrac{2x^2+7x-4}{2x^2-32}=\\ \dfrac{2x^2+8x-x-4}{2(x^2-16)}=\\ \dfrac{2x(x+4)-1(x+4)}{2(x-4)(x+4)}=\\ \dfrac{(2x-1)(x+4)}{2(x-4)(x+4)}=\\ \dfrac{2x-1}{2(x-4)}$