READING QUESTION PLEASE HELP :3

I’m stuck can someone help me thank you

Airida [17]

Answer:

the answer may be 127.

Step-by-step explanation:when you add 90° + 37° you will get the answer 127

I am not sure.

3 0

3 years ago

If f(a)=(a•a•a)-(a•a) + a-1 what is the value of f(-3)?

Elena L [17]

Answer:

-40

Step-by-step explanation:

f(a) = a³ - a² + a - 1

f(-3) = (-3)³ - (-3)² + (-3) - 1

f(-3) = (-27) - (9) + (-3) -1

f(-3) = -27 - 9 -3 - 1

f(-3) = -40

3 0

3 years ago

PLZ HURRY ITS TIMEDDDDD

GaryK [48]

A. 1/5k - 2/3j and -2/3j + 1/5k

Step-by-step explanation:

Equivalent expressions are expressions that are the same even though they may appear different.When you plug in a value to represent a variable in these expression, they will give same answer when simplified.

In

1/5k - 2/3j and -2/3j + 1/5k you notice the operation signs in the terms has been maintained though the position of the terms shifted.

Learn More

Equivalent expressions :brainly.com/question/280220

Keywords: expressions, equivalent

#LearnwithBrainly

8 0

3 years ago

Read 2 more answers

A Tessellation has no________. A) gaps or overlaps B) translations C) repeated figures

ozzi

A tessellation has no A) gaps or overlaps, as a tessellation is all about repeated figures, which can be translated onto other figures, this produces a pattern.<span />

8 0

3 years ago

The 2008 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, included the question, "Ho

vitfil [10]

Answer:

Therefore, the sampling distribution of $\bar{x}$ is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The 95% interval estimate of the population mean $\mu$ is

LCL = 7.431 hours to UCL = 10.569 hours

Step-by-step explanation:

Let X be the number of hours a legal professional works on a typical workday. Imagine that X is normally distributed with a known standard deviation of 12.6.

The population standard deviation is

$\sigma = 12.6 \: hours$

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

The sample size is

$n = 250$

The sample mean is

$\bar{x} = 9 \: hours$

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The population mean would be the same as the sample mean that is

$\mu = \bar{x} = 9 \: hours$

The sample standard deviation would be

$s = {\frac{\sigma}{\sqrt{n} }$

Where is the population standard deviation and n is the sample size.

$s = {\frac{12.6}{\sqrt{250} }$

$s = 0.7969 \: hours$

Therefore, the sampling distribution of $\bar{x}$ is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The population mean confidence interval is given by

$\text {confidence interval} = \mu \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sampling size, s is the sample standard deviation and is the t-score corresponding to a 95% confidence level.

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 250 - 1 = 249

From the t-table at α = 0.025 and DoF = 249

t-score = 1.9695

$MoE = t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\\\MoE = 1.9695\cdot \frac{12.6}{\sqrt{250} } \\\\MoE = 1.9695\cdot 0.7969\\\\MoE = 1.569\\\\$

So the required 95% confidence interval is

$\text {confidence interval} = \mu \pm MoE\\\\\text {confidence interval} = 9 \pm 1.569\\\\\text {LCI } = 9 - 1.569 = 7.431\\\\\text {UCI } = 9 + 1.569 = 10.569$

The 95% interval estimate of the population mean $\mu$ is

LCL = 7.431 hours to UCL = 10.569 hours

8 0

3 years ago