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3 years ago

Which one of these pictures is not like the other? Explain what makes it different using ratios.

Mathematics

1 answer:

KonstantinChe [14]3 years ago

4 0

Answer:

2 and 3

Step-by-step explanation:

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The temperature at 6pm was 0 degrees Fahrenheit at 10 pm the temperature was -11.2 degrees Fahrenheit write an expression that y

lana66690 [7]

The answer is the temperature goes down 2.8° every hour and the expression is x=-11.2/4 because 4 is how many hours between 6pm and 10pm and its -11.2 because that was how much the temperature dropped from 6pm to 10pm

8 0

3 years ago

I’m too lazy to do all of this and I’m also a little confused on it, and I also have more hw besides this one, so ima need all t

Oliga [24]

Answer:

14. 70% of 20000 is 14000. 25% of 14000 is 3500. 3500 students applied.

15. The percentage of 4000 that 2600 equates to would be 65%.

16. 4% of 33000 is 1320.

16b. Double of 1320 is 2640.

17. 3% of 110 + 275 + 200 + 145 is 21.9. 97% of that is 711.1. Total is 730.

18. There are 1656 men working. Total of 1380 + 1656 is 3036. Two ways to solve this are:

Honestly I can't think of two. Sorry, my brain is completely fried today.

19. 760 in sales commissions to meet the wage amount.

20. The agency gets 21010. 30% of that is 6303. This is explained by owning a calculator or simple value elimination.

6 0

2 years ago

Read 2 more answers

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

2d(3*6)=48y when y=1/4

vaieri [72.5K]

Answer: d = 1/3

Step-by-step explanation: 48y = 48/4 = 12. So, 2d(18) is equal to 12. 12/18 is 2/3 so 2d has to equal 2/3. That means d = 1/3.

8 0

2 years ago

Harley had $250.00 in her savings account in january. In july, she had $425.00. what is the percentage of increase in her saving

zlopas [31]

Answer:

Step-by-step explanation:

425-250=175

175/250=0.7

70%

3 0

3 years ago