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Andrei [34K]
3 years ago
12

who will give my answer I will mark as a brand list and follow in your back please give all the answer of the question desert 2

question only ​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

Answer:

Question 2. 12% of 650 = 78

Step-by-step explanation:

100% = 1 in decimal form.

This is because finding 100% of something is the same as multiplying it by 1:

E.g. 100% of 10=10,  10x1 = 10

Therefore to find a percentage of something, we simply need to multiply it by the decimal form of that percentage. For example, if we were finding 50% of 10 (half), 50% in decimal form is 0.5, 10x0.5 = 5

The percentage here is 12%, we can find the decimal form by dividing it by 100, 12/100 = 0.12

So, in order to find 12% of 650, we just need to multiply 650 by 0.12:

650x0.12 = 78

12% of 650 = 78

Hope this helped!

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Help plz ill give u BRAINEST ​
d1i1m1o1n [39]

Answer:

First option, relation 1 and relation 4

Step-by-step explanation:

Because they both cross one of the two axes once, which from what I remember, makes it a function.

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3 0
2 years ago
Find the Value of each variable that makes the equation true.
alexdok [17]
1.) 0
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3.) -3

Please comment for concerns please likeb
8 0
2 years ago
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Masteriza [31]

Answer:

  C

Step-by-step explanation:

The first number on the mechanic's list is the one that is most negative. The negative numbers on the list are ...

  -3/16, -1/4, -1/16

These are easier to compare if they have a common denominator:

  -1/4 = -4/16

So, the numbers are ...

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8 0
3 years ago
Please help me.
True [87]
Not sure if y-2x=10 or y-2x=-10

I'll solve both
later you will see that 10 or -10 is irrelevant

find slope first since perpendicular lines have slopes that multiply to -1
the slope from form ax+by=c is -a/b
-2x+y=?
slope=-(-2)/1=2


perpendicualr
2 times what=-1
what=-1/2

y=mx+b
m=slope
we know slope is -1/2
y=-1/2x+b
find b
subsitut eht point (9,-5)
(x,y)
x=9 and y=-5
-5=-1/2(9)+b
-5=-9/2+b
add 9/2 to both sides
-1/2=b

the equation is
y=-1/2x-1/2
8 0
3 years ago
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