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3 years ago

What coordinates best represent the location of point K on the coordinate plane.

Mathematics

1 answer:

Sindrei [870]3 years ago

8 0

Answer:

-7, -4

Step-by-step explanation:

The squares are marked by units of 2. It looks like you did not take that into account when you entered your y coordinate.

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Law Incorporation [45]

Answer:

THE 3RD ONE

Step-by-step explanation:

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3 years ago

a 10-foot section of a certain rope weighs 8 ounces. What is the length, in feet, of a section that weights 3 pounds? can you pl

Ostrovityanka [42]

Create and solve an equation of ratios:

10 ft 8 oz
------- = -------
x 48 oz (note that 3 lb = 48 oz)

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3 years ago

The sum of two numbers is 19. The difference is 9. What are the two numbers?

Nostrana [21]

Answer:

the two numbers are 8 and 8

7 0

2 years ago

Read 2 more answers

A right cylinder has a diameter of 40 mm and a height of 30 mm, as shown. Semester Test, Part 1 What is the volume of the cylind

sukhopar [10]

Volume = Area * height
= (pi/4)*D^2 * h
= (pi/4)*(40)^2 * 30
= 37,680 mm3
so, the answer is (a)

8 0

3 years ago

Read 2 more answers

natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

$\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.$

b) In matrix form this is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)$

c) The determinant is

$\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16$

d) Find three determinants:

$\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608$

$\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368$

$\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304$

So,

$x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19$

e) If the store doubled all prices and inventory, then the new matrix is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)$

7 0

3 years ago