Question

PLEASE PLEASE PLEASE HELP ME​

Answer 1

Answer:

$\large\boxed{\dfrac{1}{45}}$

Step-by-step explanation:

1.

2 yellow marables of 10 all marables

$P(A_1)=\dfrac{2}{10}=\dfrac{1}{5}$

2.

1 yellow marable of 9 all marables

$P(A_2)=\dfrac{1}{9}$

$P(A)=P(A_1)\cdot P(A_2)\\\\P(A)=\dfrac{1}{5}\cdot\dfrac{1}{9}=\dfrac{1}{45}$