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Ghella [55]
3 years ago
13

What is the minimum value of 2x + 2y in the feasible region? (0,7) (3,7) (6,3) (6,0)

Mathematics
1 answer:
topjm [15]3 years ago
8 0
Graph the feasible region for the following constraints: x + y < 5. 2x + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + 2y = 0. x - 2y = 0.
hence i would go for
<span>(6,3)</span>
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Given that (5,4) is on the graph of f(x), found the corresponding point for the function f (x)+4
yarga [219]

Answer:

The corresponding point is (5,8)

Step-by-step explanation:

In this problem we know that

The rule of the transformation is equal to

(x,f(x)) ------> (x,f(x)+4)

so

for the point (5,4)

x=5, f(x)=4

substitute

(5,4) ------> (5,4+4)

(5,4) ------> (5,8)

therefore

The corresponding point is (5,8)

5 0
3 years ago
HELP ASAP
kari74 [83]

Answer:

2. 4a+2c = 5000

4. a + c = 1600

Step-by-step explanation:

8 0
3 years ago
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a park is 4 times as long as it is wide. if the distance around the park is 12.5 kilometers, what is the area of the park?
blsea [12.9K]
So, first, what are the two sides?

let's call then x and y

we know that 2(x+y)=12.5 (that's the distance around)

so that means that x+y=6.25 (I just divided both by 2)

now, x=4y (from "4 times as long as it is wide")

so we can substitute:

x+4x=6.25

5x=6.25

x=1.25

so one side, is 1.25 and the other will be 1.25*4=5

and for the area we multiply the two:

1.25*5=6.25 square kilometers, and this is the answer!
7 0
3 years ago
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Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot
klemol [59]

Answer: The distance around the lot is given by

4\frac{1}{20}\ miles

Step-by-step explanation:

Since we have given that

Length of rectangular lot is given by

1\frac{1}{8}\\\\=\frac{9}{8}\ miles

Width of rectangular lot is given by

\frac{9}{10}\ mile

We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles

Hence, the distance around the lot is given by

4\frac{1}{20}\ miles


3 0
3 years ago
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One hamster weighs 300 g less than half
Mars2501 [29]

Answer:

1125&825

Step-by-step explanation:

6 0
3 years ago
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