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3 years ago

The line on the graph passes through the points A (0, 6) and B (3, 0)

Mathematics

1 answer:

Romashka [77]3 years ago

7 0

Answer:

a) -2

b) ½

c) y= ½x +6

Step-by-step explanation:

Please see the attached pictures for the full solution.

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If $10,000 is borrowed at an APR of 18%, for a period of 5 years and payments are made monthly, what will be the monthly payment

Soloha48 [4]

Answer:

$381.29

Step-by-step explanation:

10000(1+.18)5

10000(1.18)5

Amount due $22877.58

since 5 years x 12 months =60 months

monthly payment is 22877.58÷60 = $381.29

4 0

3 years ago

1) find the equation of the line parallel to

In-s [12.5K]

<u>Answer:</u>

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

<u>Solution:</u>

<u><em>1) find the equation of the line parallel to x-5y=6 and through (4,-2).</em></u>

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

<u><em> 2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)</em></u>

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

3 years ago

Burak runs a Turkish restaurant. One day, he records that he sells two popular dishes, sasuka and pide, in the ratio 3:5. If Bur

Natasha2012 [34]

Step-by-step explanation:

<h2>sasuka:pire</h2><h3> 3:5</h3><h3>3/8:5/8=3/8×24×8/5 </h3>

= 14.4

7 0

3 years ago

One of the angles in an intersecting line mesures 30

asambeis [7]

Think of the point, P, where the lines intersect as the center of a circle. The four angles with vertex P add up to 360 degrees. The given angle and its paired vertical angle are both 30 degrees. So, the other two angles are also vertical angles with sum 300 degrees (so each of them is a 150 degree angle).

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3 years ago

PLEASE HELP!! <br>A line is rotated. Which of these could be the result?

motikmotik

Answer:

Step-by-step explanation:

4 0

3 years ago

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