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3 years ago

At the mall, Leona bought a T-shirt and a book for a total of $34. The book cost $12. How much did the T-shirt cost?

Mathematics

2 answers:

wolverine [178]3 years ago

7 0

Answer:

a. the cost of the t-shirt

b. x+12=34

c. x=22

d. t-shirt cost 22$

Tatiana [17]3 years ago

3 0

1: The unknown information is how much the t shirt costs.

2: x + 12 = 34

3 & 4: The t-shirt would cost $22, because 34 - 12 = 22.

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3 years ago

Thanks for the help, question below :)

pickupchik [31]

Answer:

a: $40h+75f=800,h+f=13$

b: 5

c: 8

Step-by-step explanation:

Explanation for a: Making the equations

Assuming h is the amount of half-page ads and f is the amount of full page ads, we can create the equations $40h+75f=800,h+f=13$ since the total cost will be 800$, and we have a total of 13 ads.

Explanation for b: Solving for h

We can now solve for one of the variables using elimination. Let’s multiply the expression $h+f=13$ by -75.

$-75h - 75f = -975$

Great! Now let’s add the equations.

$40h + 75f = 800\\\\-75h - 75f = -975$

Adding these equations, we get

$-35h = -175$

Divide both sides by -35, and we get $h = 5$ .

Explanation for c: Solving for f

We can now substitute h inside the equation $h + f = 13$ .

$5 + f = 13\\\\f = 13-5\\\\f = 8$

Hope this helped!

6 0

3 years ago

Read 2 more answers

A dot-com company ships products from three different warehouses (A, B, and C). Based on customer complaints, it appears that 3%

Firlakuza [10]

Answer:

The probability of getting defective product from warehouse C is 0.3448

Step-by-step explanation:

Missing question "Assume that Ware houses A, B and C ship 30%, 20% and 50% of the dot-com's sales respectively.

P(A) = Probability of product that comes from warehouse A

P(B) = Probability of product that comes from warehouse B

P(C) = Probability of product that comes from warehouse C

P(A) = 30% = 0.30, P(B) = 20% = 0.20, P(C) = 50% = 0.50

Let D denotes the number of defective products

P(D|A) = 3% = 0.03

P(D|B) = 5% = 0.05

P(D|C) = 2% = 0.02

The probability of getting defective product from warehouse C is as below using the Bayes Rule

P(C|D) = P(D|C) P(C) / P(D|A)P(A) + P(D|B)P(B) + P(D|C)P(C)

P(C|D) = 0.02 * 0.50 / (0.03*0.30) + (0.05*0.20) + (0.02*0.50)

P(C|D) = 0.01 / 0.009 + 0.01 + 0.01

P(C|D) = 0.01 / 0.029

P(C|D) = 0.3448

Therefore the probability of getting defective product from warehouse C is 0.3448.

3 0

3 years ago