The sum of the measures of the exterior angles of a regular 5-gon, one at each vertex, is __________ the sum of the measures of
the exterior angles of a regular 9-gon, one at each vertex.
less than
equal to
greater than
1 answer:
The exterior angles of a regular pentagon has a measure of 360-108= 252 degrees
the sum of these exterior angles will be 5*252=1260 degrees
a regular nonagon (9-gon) has the exterior angles measure of 360 -140 = 220 degrees
the sum of these exterior angles of a nonagon will be equal 9*220=1980 degrees
so from these result that
the sum of the measures of the exterior angles of a regular 5-gon is less than the sum of the measures of the exterior angles of a 9-on
hope this will help you
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Answer:
$360
Step-by-step explanation:
I am pretty sure this is the answer i am not that sure. But $9,000 at 8% is 760
and 360 is half of 760
Wait isn’t it a? I’m not sure tho
-9-6+12h+40=22
12h+25=22
12h=-23
h=-23/12
Easy, the second one. Both figures seem congruent.
Answer:
r = 1
Step-by-step explanation:
Solve for r
by simplifying both sides of the equation, then isolating the variable.
