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GenaCL600 [577]
3 years ago
14

If ABCD is a parallelogram, what can we say about the diagonals BD and AC?

Mathematics
2 answers:
myrzilka [38]3 years ago
7 0

The answer is B. The diagonals of a parallelogram bisect each other.

BD ≅ AC.

lidiya [134]3 years ago
4 0
B. The diagonals bisect each other.
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Which statement is false A the inequality sign alwats opens up to the largers number. B the greater number in the equality is al
Hatshy [7]

Answer:

D inequality sign always open up to a smaller number

Step-by-step explanation:

8 0
3 years ago
Using the chart "Amount of $1 at Compound Interest" from previous reading section "More Compound Interest", find the total amoun
vitfil [10]

Answer:

Step-by-step explanation:

the formula used for any interest other then continuously is

A=P(1+r/n)^nt

so... r=rate in decimal form ONLY n=how often interest is paid t=time passed

A=3000(1+.08/1)^(1)(5) = annually

A=3000(1+.08/2)^(2)(5)

A=3000(1+.08/4)^(4)(5)

use you calculator to get the answer

it is good practice to use your calculator now because soon you will be using it for population questions and those need to be entered very carefully.

7 0
3 years ago
How do you put 7:5 in a statement
Evgen [1.6K]
In a survey over whom prefers orange juice and whom prefers milk, 7 kids said they liked orange juice, and 5 chose milk. 

Hope this helped :)
5 0
2 years ago
Read 2 more answers
Which property refers to "regrouping" the terms in the expression 9 (2-x) = 18 - 9x ?
Aliun [14]
The answer is C- Distributive Property because you times everything in the bracket by the value connected to it:
9 times 2=18
9 times x = 9x
= 18 - 9x
3 0
2 years ago
Read 2 more answers
Find five consecutive integers such that: "the sum of the first and 4 times the third is equal to 60 less than 3 times the sum o
Monica [59]

Consecutive integers are integers that come one after another in order. For example, 2, 3, and 4 are all consecutive integers, as well as 100, 101, and 102. In general, if we have some integer n, the consecutive integers following it will be n + 1, n + 2, n + 3, etc. Here, we have five. If we

  • Call the first integer n,
  • Then the second integer will be n + 1,
  • The third will be n + 2,
  • The fourth will be n + 3,
  • And the fifth will be n + 4.

Now, let's break down the equation in English. We'll use #1, #2, #3, #4, and #5 as stand-ins for the five integers just so we can get things set up, then we'll replace them with the expressions we came up with in the first part. Starting from the beginning of the statement, let's translate words to symbols:

  • "The sum of the first and 4 times the third" → #1 + 4 × #3
  • "is equal to" → = (maybe obvious, but still!)
  • "60 less than 3 times the sum of the second, fourth, and fifth" → 3 × (#2 + #4 + #5) - 60

Putting that all together, we get the equation

#1 + 4 × #3 = 3 × (#2 + #4 + #5) - 60.

Replacing our stand-ins for the expressions we came up with, it becomes

n + 4(n + 2) = 3[(n + 1) + (n + 3) + (n + 4)] - 60

We can now start to simplify our equation to find n (the first integer) and the rest will follow easily from that. I'll start by focusing on the left side. We can distribute and combine like terms like so:

n + 4(n+2) = n + 4n + 8 = 5n + 8

Dealing with the right, we can get rid of some redundant parentheses and carry out the same process:

3[(n + 1) + (n + 3) + (n + 4)] - 60 = 3(n + 1 + n + 3 + n + 4) - 60

= 3(3n + 8) - 60 = 9n + 24 - 60 = 9n - 36

Our simplified equation now becomes

5n + 8 = 9n - 36.

Subtracting 5n from either side:

8 = 4n - 36

Adding 36 to either side:

44 = 4n

And dividing either side by 4:

11 = n.

We now know that our first integer is 11, which means that our 5 consecutive integers are 11, 12, 13, 14, and 15.

7 0
3 years ago
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