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Goshia [24]
3 years ago
15

You are saving for a new laptop that cost $499. You work two jobs: cleaning your grandparents' house for $15 an hour and mowing

lawns for $10 an hour. Write an inequality for how much you must earn cleaning (c) and mowing (m) in order to earn at least $499.
May I have help please.
Mathematics
2 answers:
Gekata [30.6K]3 years ago
4 0
15c+10m is greater then or equal to 499
xxMikexx [17]3 years ago
3 0

Answer:

15x + 10x less than it equal to 499

Step-by-step explanation:

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You're killing me! 7x7x7x7x7=? Think about... You are multiplying 7 five times. When use use an exponent your are simply showing the amount of time 7 (or whatever your number is) has been multiplied by itself in a more compact form. For example: 5^8=5x5x5x5x5x5x5x5 Or 4x4x4=4^3
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A student writes 5y*3 to model the relationship the sum of 5y and 3. explain the error
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___________is an expected error based only on the observations limited to a sample taken from a population
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━━━━━━━☆☆━━━━━━━

▹ Answer

<em>1. Sampling error</em>

▹ Step-by-Step Explanation

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3 0
3 years ago
A school chorus has 60 sixth-grade students and 48 seventh-grade students. The music director wants to make groups of performers
san4es73 [151]
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3 0
3 years ago
The number of square feet per house is normally distributed with a population standard deviation of 154 square feet and an unkno
11111nata11111 [884]

Answer: (1500.66,1599.34)

Step-by-step explanation:

Confidence interval for population mean:

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

,where \overline{x} = Sample mean , n= Sample size, z* = critical two tailed z-value , \sigma = population standard deviation.

As per given , we have

n= 16

\sigma = 154 square feet

\overline{x}= 1550 square feet

\alpha= 1-0.80 = 0.20

Critical z-value = z_{\alpha/2}=z_{0.2/2}=z_{0.1}=1.2815

Confidence interval for population mean:

1550\pm (1.2815)\dfrac{154}{\sqrt{16}}\\\\ = 1550\pm (1.2815)\dfrac{154}{4}\\\\= 1550\pm 49.33775\\\\ =(1550-49.33775,\ 1550+49.33775)\\\\\approx (1500.66,\ 1599.34)

Required confidence interval:  (1500.66,1599.34)

6 0
3 years ago
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