Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer:
4x^2 +84x+440
840 in^2
Step-by-step explanation:
The length of the picture and frame is x+ 22+x= 2x+22
The width of the picture and frame is x +20+x = 2x+20
Area is length times width
A = (2x+22) *(2x+20)
We can FOIL to find the area
first 2x*2x = 4x^2
outer 2x*20 =40x
inner 2x*22 = 44x
last = 22*20 = 440
Add these together
4x^2 +40x+44x+440
4x^2 +84x+440
b. x=4
4x^2 +84x+440
4(4)^2 +84(4) +440
4*16 +336+440
64+776
840
