Enter a range of values for x.

Mathematics

2 answers:

WARRIOR [948]2 years ago

8 0

Answer:

Step-by-step explanation:

i dont know sorry

abruzzese [7]2 years ago

6 0

<h3>Answer: 3 < x < 34</h3>

=============================================================

Explanation:

Ignore the sides that are 'a' units long.

We'll compare the sides that are 26 units and 27 units long. We see the 27 unit side is larger, which makes the 93 degree angle larger than the 3x-9 degree angle.

Symbolically, we would say

3x-9 < 93

At the same time, the 3x-9 is also larger than 0

3x-9 > 0 or 0 < 3x-9

Put together, we can form this compound inequality

0 < 3x-9 < 93

-------------------

Let's isolate x like so

0 < 3x-9 < 93

0+9 < 3x-9+9 < 93+9 .... add 9 to all sides

9 < 3x < 102

9/3 < 3x/3 < 102/3 .... divide all sides by 3

3 < x < 34

x is any number between 3 and 34, but cannot equal either endpoint

For example, x = 10 is valid since 3 < 10 < 34 is true. But x = 50 is not a solution since 3 < 50 < 34 is false. We can't have x = 3 and we also can't have x = 34 either, but we can have anything in between those endpoints.

You might be interested in

PLEASE HELP 8th GRADE MATH QUESTION OVER HERE!!!

patriot [66]

The side AB measures option 2. $\sqrt{20}}$ units long.

Step-by-step explanation:

Step 1:

The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).

The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.

To calculate the distance between two points, we use the formula $d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}.$

where ( $x_{1},y_{1}$ ) are the coordinates of the first point and ( $x_{2},y_{2}$ ) are the coordinates of the second point.

Step 2:

For A (4, 5) and B (2, 1), ( $x_{1},y_{1}$ ) = (4, 5) and ( $x_{2},y_{2}$ ) = (2, 1). Substituting these values in the distance formula, we get

$d=\sqrt{\left(2-4\right)^{2}+\left(1-5}\right)^{2}} = \sqrt{\left(2\right)^{2}+\left(4}\right)^{2}}=\sqrt{20}}.$