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fiasKO [112]
3 years ago
5

Consider circle N with radius 30 cm and θ = radians. What is the approximate length of minor arc LM? Round to the nearest tenth

of a centimeter.

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0
The arc of LM would be 30 cm. Assuming that <span>θ = radians means that theta equals ONE radian (there is no other value given), then the arc would be the same length as the radius. The definition of a radian is an angle in which the arc is the same length as the radius of the circle. 

Hope this helps!</span>
anygoal [31]3 years ago
4 0

Answer: its 15.7

Step-by-step explanation:

i just did the test

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<span><span> STEP 1. </span><span><span>x/5+6= 36
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How should the decimal point in 8.403 be moved to determine the product of 10,000 × 8.403?
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Answer:

84,030.00 (Move the decimal point 4 to the right)

Step-by-step explanation:

When multiplying, move the decimal to the right! When dividing, move the decimal to the right!

Since, 10,000 has 4 zeros, we will want to move the decimal point four places to the right!

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Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and i
Mandarinka [93]

Neither statement 1, nor statement 2 are correct

The given Stephon's statements are;

Statement 1; \mathbf{\lim \limits  _{x \to -3} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to -3} f(x) = 1}

Statement 2; \mathbf{\lim \limits  _{x \to 1} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to 1} f(x) = 1}

The analysis of the graph and reason for the answer

From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement

The limits of the domain and range of the graph includes;

\mathbf{\lim \limits  _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}

f(x) = Defined for -∞ ≤ x < -3

Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write

\mathbf{\lim \limits  _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}

From we above, we have that neither statement 1, nor statement 2 are correct

Learn more about open and closed circles on graph lines

brainly.com/question/8648835

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What is the product?<br> -9x(5-2x)<br> 2
fiasKO [112]

-9x(5-2x)

What does the second two mean?

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