Answer:
The mean number of adults who would have bank savings accounts is 32.
Step-by-step explanation:
For each adult surveyed, there are only two possible outcomes. Either they have bank savings accounts, or they do not. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

In this problem, we have that:

If we were to survey 50 randomly selected adults, find the mean number of adults who would have bank savings accounts.
This is E(X) when
.
So

The mean number of adults who would have bank savings accounts is 32.
Answer:
(1,8) and (-3,0)
Step-by-step explanation:
We simply graph the two functions in the same graph. The solution set to the system is given by the points where the two functions intersect. For this case, the two functions intersect at;
(1,8) and (-3,0)
The solution set is thus; (1,8) and (-3,0)
Check the attachment below;
Answer:
The prevalence rate of flu cases requiring hospitalization thus far in 2018 is:
= 0.13%
Step-by-step explanation:
a) Data and Calculations:
Population of Portland, ME = 70,000
Number of flu cases requiring hospitalization on February 1st, 2018 = 43
Number of flu cases requiring hospitalization on July 4th, 2018 = 90
The prevalence rate of flu cases requiring hospitalization thus far in 2018 = 90/70,000 * 100 = 0.13%
b) The prevalence rate represents the proportion of the population of Portland, ME, who have the flu at the time that the Maine Public Health Department reported the number of flu cases requiring hospitalization on July 4th, 2018.
Answer:
8
Step-by-step explanation: