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3 years ago

You want to construct a box-and-whisker plot from a data set. What is the first thing you should do?please help

1 answer:

7 0

It would most likely be (B) order the data values from least to greatest. Because I think you would most likely to get the plot much easier. <span />

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Which of the following best describes an output NEED HELP PLS

kirill [66]

Answer:

I DO FLVS AS WELL AND I GOT THAT ONE WRONG

Step-by-step explanation:

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3 years ago

The product of a number and -3 increased by 8 is 20

Roman55 [17]

Answer:

The answer would be -4.

Step-by-step explanation:

This is because the product of a number and -3 must be 8 less than 20, which is 12. And -3 times -4 is 12.

8 0

4 years ago

Which graph models the equation y = 3.5x?

devlian [24]

The answer is c be us wit is goin up by 3.5/1

4 0

3 years ago

Read 2 more answers

URGENT EXPLANATION AND SOLVING

Alex787 [66]

$\cfrac{a}{\sin(a)} = \cfrac{b}{\sin(b)} 
$

$\cfrac{31}{\sin(42)} = \cfrac{37}{\sin(x)} 
$

$31\sin(x) = 37 \sin(42)$

$\sin(x) = \cfrac{37 \sin(42) }{31}$

$x = \sin^{-1}(\cfrac{37 \sin(42) }{31} )$

$x = 53 \textdegree$

Answer: 53°

7 0

4 years ago

Read 2 more answers

Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: $(x-h)^2+(y-k)^2=r^2$

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

$(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36$

So, equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

5 0

3 years ago