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viktelen [127]
3 years ago
11

The Mail Merge Wizard can be found in the drop-down list of the _____ icon.

Computers and Technology
2 answers:
LuckyWell [14K]3 years ago
5 0
It would have to be letter B.
alexgriva [62]3 years ago
4 0

Answer:

The correct answer to the following question will be option B. Labels.

Explanation:

Mail merge is composed of combining letters, mail and mailing labels from form letters to mass mailing. This feature of Microsoft word saves your efforts and time, it is also known as Print merge.

Following are the labels of wizards of mail merge which is given below:

Step 1: Pen the tab of mailing which appears in the menu bar.

Step 2: Click on the start merge

Step 3: Choose the wizard of step by step mail merge.

Step 4: Choose the labels of mail merge and also click on the Next button.

Step 5: Select the starting template and click on the next button.

Step 6: After that write the recipient address and click on the finish button to finish the mail merge.

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four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Argon atom. A n = 2, l =0,
marshall27 [118]

Answer:

  • n = 3
  • l  = 1
  • m_l = 1
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Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

  • 1s² 2s² 2p⁶ 3s² 3p⁶   : 2 + 2 + 6 + 2 + 6 = 18 electrons.

The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

  • n = 3

  • l = 1 (orbitals s correspond to l = 0, orbitals p correspond to l  = 1, orbitals d, correspond to l  = 2 , and orbitals f correspond to  l = 3)

  • m_l can be -1, 0, or 1 (from - l  to + l )

  • the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

  • (3, 1, -1 +1/2)
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  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
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