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creativ13 [48]
3 years ago
7

Bastian was able to map quadrilateral OPQROPQRO, P, Q, R onto ONMLONMLO, N, M, L using a reflection and a dilation.

Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

C. There is no error. This is a correct conclusion.

Step-by-step explanation:

Reflection is a transformation in which a given image is flipped across a reflection line  to create the image. Each point of the image (e.g ONML) maintained their distance from the line as the initial object (e.g OPQR). The size of the object and image are the same after a reflection.

Dilation involve resizing the dimensions of a given object to produce an image of the same shape. It requires a scale factor to either increase or decrease the dimensions of the object.

Comparing quadrilaterals OPQR and ONML. Drawing a reflection line vertically through O, it can be observed that OPQR was first reflected. Then  enlarged by a scale factor to produce ONML, thus dilation.

Therefore, there is no error in Bastian's conclusion.

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Step-by-step explanation:

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3 years ago
Prove that for any natural n the number 3^(n+4)−3^n is divisible by 16.
gtnhenbr [62]

Answer:

Proved (See Explanation)

Step-by-step explanation:

Show that 3ⁿ⁺⁴ - 3ⁿ is divisible by 16.

This is done as follows

\frac{3^{n+4} - 3^n}{16}

From laws of indices;

aᵐ⁺ⁿ = aᵐ * aⁿ.

So, 3ⁿ⁺⁴ can be written as 3ⁿ * 3⁴.

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\frac{3^n * 3^4 - 3^n}{16}

Factorize

\frac{3^n(3^4 - 1)}{16}

\frac{3^n(81 - 1)}{16}

\frac{3^n(80)}{16}

3ⁿ * 5

5(3ⁿ)

<em>The expression can not be further simplified.</em>

<em>However, we can conclude that when 3ⁿ⁺⁴ - 3ⁿ is divisible by 16, because 5(3ⁿ) is a natural whole number as long as n is a natural whole number.</em>

3 0
3 years ago
An arithmetic sequence with a third term of 8 and a constant difference of 5.
larisa [96]
An arithmetic sequence (a_n) is as follows:

a_1\\a_2=a_1+d\\a_3= a_1+2d\\a_4=a_1+3d,... where a_1 is the first term and d is the constant difference, 

thus, we see that the n'th term of an arithmetic sequence is a_n=a_1+(n-1)d


in our particular case d=5, the third term is 8, so we have:

a_3=8=a_1+2\cdot5\\\\8=a_1+10\\\\a_1=-2


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3 years ago
Bananas sell for $0.44 pounds. How much will 6 pounds of bananas cost.
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Answer:

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8 0
2 years ago
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The radius of a circular plate is 12 centimeters. What is the area, in square centimeters, of this plate? Write your Anwer using
lesya [120]

Answer:

The area of circular plate is <u>144π square centimeters</u>.

Step-by-step explanation :

<h3><u>Solution</u> :</h3>

Here, we have given that the radius of circular plate is 12 centimeters.

So, finding the area of circular plate by substituting the values in the formula :

\longrightarrow{\pmb{\sf{Area_{(Circle)} = \pi{r}^{2}}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi{(12)}^{2}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi{(12 \times 12)}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi{(144)}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi \times 144}}

\longrightarrow{\sf{Area_{(Circle)} = 144\pi}}

\star{\underline{\boxed{\frak{\purple{Area_{(Circle)} = 144\pi\:  {cm}^{2}}}}}}

Hence, the area of circular plate is 144π square centimeters.

\rule{300}{2.5}

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2 years ago
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