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lesya692 [45]
2 years ago
7

If 8 times a number is added to twice the​ number, the result is 60. the solution is

Mathematics
2 answers:
kogti [31]2 years ago
7 0

Answer:

<u>The number is 6</u>

Step-by-step explanation:

<u>Given :-</u>

8N + 2N = 60

<u>To Find :-</u>

N

<u>Solving :-</u>

8N + 2N = 60

10N = 60

<u>N = 6</u>

<u />

<u>Solution :-</u>

<u>The number is 6</u>

Andrei [34K]2 years ago
3 0

Answer:

(8 * x) + 2x = 60

8x + 2x = 60

10x = 60

/10   /10

x = 6

8 is a constant that is being multiplied by an unknown number which we will name x. It is then being added to two times the unknown number(x), so we multiply x by 2, which is 2x. The final product will be 60, so in the equation it'll then equal 60.

We consider "a number" to be a variable that withholds an unknown value, which is x (or any other variable you prefer).

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Find the distance between the points (2, -9) and (-1, 4).
ollegr [7]

Answer:

A. 13.34

Step-by-step explanation:

This is the formula d=√((x_2-x_1)²+(y_2-y_1)²)

Plug in

d=√(-1-2)² + (4+9)²

d= √9 + 169

d= √178

d= 13.34

6 0
3 years ago
After a researcher adds 5 points to every score in a sample, the standard deviation is found to be s = 10. the original sample h
12345 [234]
A, true.

If you add 5 points to every score, that makes the difference between them 5 points higher.
4 0
3 years ago
The length of a rectangle is twice that of its width. If the area of the rectangle is 72 square inches, then find the length and
Blizzard [7]

Well, we should start by listing the factors

1,2,3,4,6,8,9,12,16,24,36,72

You can put these in pairs if it will help you,

1*72  2*36  3*24  4*16  6*12  8*9

If you look, you can see that in only one pair the length is twice the width.

So your answer is

W=6

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6 0
2 years ago
Problem PageQuestion The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate paramet
asambeis [7]

Answer:

<em>t = 1.51</em>

Step-by-step explanation:

<u>Exponential Model</u>

The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.

The model can be expressed as

M=M_oe^{kt}

In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.

The value of k is not precisely given in the question, we are assuming k=-0.2

The model is now

M=M_oe^{-0.2t}

We are required to compute the time it takes the mass to reach one-half of its initial value:

\displaystyle \frac{M_o}{2}=M_oe^{-0.2t}

Simplifying

\displaystyle \frac{1}{2}=e^{-0.2t}

Taking logarithms

\displaystyle ln\frac{1}{2}=ln(e^{-0.2t})=-0.2t

Solving for t

\displaystyle t=-\frac{ln\frac{1}{2}}{0.2}=1.51

6 0
3 years ago
Suppose s varies directly with t. When t27, s=3. What is s when t=632
jekas [21]

Answer:

G 7

Step-by-step explanation:

If t= 27 when s=3  27/3=9

the t=63 when s= 7    63/7= 9

8 0
2 years ago
Read 2 more answers
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