Very easy:
Common denominator:
-5/10w - 3/5 = 2/10w
- 3/5 = 7/10w
-30 = 35w
-30/35 = w
-6/7 = w
That's how you do it mate ;)
Usually I would use my head, but you can use whatever you want.
Answer:
Step-by-step explanation:
Perimeter of a rectangle = 2(L +W)
Given L = W + 2 and the perimeter is greater than 112 meters?
P rect < 2(L +W) L = W + 2
P rect < 2(W + 2 +W)
< 2(2W+2)
112 < 4W + 4 solve for W
(112 - 4)/4 < (4W +4 - 4)/4
108/4 < (4W + 0)/4
27 < W
the width has to be greater than 27 meters
Answer:
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2
Step-by-step explanation:
Parallel lines have same slopes.
Line 1, L1: 5x-2y=20 is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.
5x-2y = 20
-2y = -5x+20
y = (-5/-2)x+20/(-2)
y = (5/2)x-10 hence m1=5/2 and y-intercept is -10
Line 2 , L2: y-y1 = m (x-x1), m=m2=m1=5/2
Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2