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3 years ago

What are all the powers of 4 in the range of 4 through 1,00? DUE TOMMAROW

Mathematics

1 answer:

AleksAgata [21]3 years ago

6 0

4, 16, 64, 256. The powers are 4 to the first. Four to the second, four to the third and four to the fourth power.

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How do you do this question?

marishachu [46]

Answer:

100

Step-by-step explanation:

│an − L│< ε

│(1 − 1/n) − 1│< 1/100

│-1/n│< 1/100

1/n < 1/100

n > 100

3 0

3 years ago

Help ASAP

krok68 [10]

Answer:

1. x=10,-10

2. x = 5

x = -5

3. x=-5

4. x ∈ {4,- 3/2}

Step-by-step explanation:

7 0

3 years ago

Describe how to find the GCF of two numbers

lions [1.4K]

You just need to know that a factor is one of the two numbers you multiply together to get a product. Prime numbers have only two factors: 1 and the number itself.

8 0

3 years ago

A class consists of 12 boys and 12 girls. The teacher picks five students to present their work to the rest of the class

Varvara68 [4.7K]

Answer:

0.01863, yes preference

Step-by-step explanation:

given that a class consists of 12 boys and 12 girls. The teacher picks five students to present their work to the rest of the class and says that the five students are being selected at random

Here selecting any 5 students from the group of total 24 students is combination because order does not matter.

Total no of ways of selecting any 5 from total 24 = $24C5\\=42504$

No of ways of selecting only 5 girls = No of ways of selecting random 5 girls from total 12 girls

= $12C5\\=792$

a) the probability be that all five students

selected are girls= $\frac{792}{42504} \\=0.01863$

b) Since the probability for selecting all girls is very small and near to 0, it is unusual to select all girls if done at random. Hence the teacher had a preference for girls.

5 0

3 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

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