<h3>Given -:</h3>
change in emitter current, ∆l(E) = 4 mA
change in collector current,∆I(C) = 3.5 mA
<h3>To find -:</h3>
value of B
<h3>Solution :-</h3>
∆I(E) = ∆I(C) + ∆l(B), here ∆l(B) is the change in base current.
4 = 3.5 + ∆l(B)
∆I(B) = 0.5 mA
<h3>Now, B = ∆l (C) ÷ ∆l (B)</h3>
B = 3.5 ÷ 0.5
B = 7.0
<h3>so, the value of A = 7.0</h3>
Answer:
r
Step-by-step explanation:......
Answer:
N=CD C=2-3 sentance
Step-by-step explanation:
two hundred ninety-six ten thousandths
I hope this helps you
8b-7b-7-2
b-9
