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denis23 [38]
3 years ago
8

HELP PLZZZZZZZZ

Mathematics
2 answers:
klio [65]3 years ago
5 0

Answer:

Hewo Asuna here

Your answer is B

Step-by-step explanation:

Hope this helps!

pychu [463]3 years ago
3 0

Answer:

Hi! The answer to your question is A. Y= -10!

Step-by-step explanation:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆

☆Brainliest is greatly appreciated!☆

<em>Hope this helps!!!</em>

<em>Stay Safe!!</em>

<em>- Brooklynn Deka</em>

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Which expressions are perfect cubes?<br> -1,000<br> 0 2721<br> 343p<br> O n30<br> ebo...<br> -1
Vikki [24]

Answer: -1000, 27r^21, g^3h^30, and -1

Step-by-step explanation:

4 0
3 years ago
Which of the numbers below are whole numbers A 0.328 B.678.79 C.159113 D.3809 E.757 F.0​
Naily [24]

Answer:

F

Step-by-step explanation:

F

zero

Anytime you have zero as a possible answer, you have to consider it carefully. Part of the whole number system is 0. They go up from there. No fraction is a whole number. No decimal is a whole number except those that are equal to  a whole number.

The rest are all decimals so they are not whole numbers. Note I just noticed that the other numbers have periods after the choice. There are other whole numbers there if that is the case.

C D E and F are all whole numbers if that is a period after their choice letters.

4 0
3 years ago
A company made a bar graph showing the amount of sales for each month in thousands of dollars. Which of the following is closest
xxTIMURxx [149]

I believe it’s A I may be wrong tho
8 0
3 years ago
What are 3 equivalent ratios to 2/5
KIM [24]
3 equivalent ratios can be:

4/10

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8/20?
3 0
3 years ago
Read 2 more answers
What is the exact value of arccos(−2√2) ?
Strike441 [17]

Answer:

See explanation

Step-by-step explanation:

The range of the cosine function is -1\le \cos x\le 1

Therefore arc \cos (-2\sqrt{2}) is not defined.

Assuming your question is rather arc \cos (-\frac{\sqrt{2}}{2})

Then arc \cos (-\frac{\sqrt{2}}{2})=\pi-arc \cos (\frac{\sqrt{2}}{2})  in the second quadrant.

arc \cos (-\frac{\sqrt{2}}{2})=\pi-\frac{\pi}{4}

arc \cos (-\frac{\sqrt{2}}{2})=\frac{3\pi}{4}

4 0
3 years ago
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