Yes. When the function f(x) = x3 – 75x + 250 is divided by x + 10, the remainder is zero. Therefore, x + 10 is a factor of f(x) = x3 – 75x + 250.
According to the remainder theorem when f(x) is divided by (x+a) the remainder is f(-a).
In this case,
f(x)=x^3-75x+250
(x+a)=(x+10)
Therefore, the remainder f(-a)=f(-10)
=x^3-75x+250
=(-10)^3-(75*-10)+250
=-1000+750+250
=1000-1000
=0.
The remainder is 0. So, (x+10) is a factor of x^3-75x+250.
Answer:
61°
Step-by-step explanation:
, QO Bisector
, Algebra
, Algebra/Sub
9514 1404 393
Answer:
(a) 15/17
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the cosine relation:
Cos = Adjacent/Hypotenuse
cos(P) = PQ/PR
cos(P) = 15/17
C. 7. because if you divide the value for the missing term (take 28 for example) and divided it by the value of i (4) you will get 7. (28÷4=7)
I believe the 4th one
an=145+an-1 and a1=20