Ask question

Ask question

All categories

2 years ago

14

(3 points) Buchtal, a manufacturer of ceramic tiles, reports on average 3.1 job-related accidents per year. Accident categories

include trip, fall, struck by equipment, transportation, and handling. The number of accidents is approximately Poisson. Please upload your work for all of the parts at the end. (0.5 pts.) a) What is the probability that more than one accident occurs per year

1 answer:

Strike441 [17]2 years ago

8 0

Answer:

0.8743 = 87.43% probability that more than one accident occurs per year

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Buchtal, a manufacturer of ceramic tiles, reports on average 3.1 job-related accidents per year.

This means that $\mu = 3.1$

What is the probability that more than one accident occurs per year?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3.6}*(3.6)^{0}}{(0)!} = 0.0273$

$P(X = 1) = \frac{e^{-3.6}*(3.6)^{1}}{(1)!} = 0.0984$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0273 + 0.0984 = 0.1257$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1257 = 0.8743$

0.8743 = 87.43% probability that more than one accident occurs per year

You might be interested in

What is the equation of a line perpendicular to y= 3/4x +12 that passes through (12, 3)

ycow [4]

Answer:

y=-4/3x-9

=

−

4

3

x

−

9

Step-by-step explanation:

First we need to get the slope of the perpendicular line

The slope of a perpendicular line is equal to the negative inverse of the slope of the given line

y

=

m

x

+

b

y

=

3

4

x

−

2

⇒

m

=

3

4

m

'

=

−

1

m

⇒

m

'

=

−

1

3

4

⇒

m

'

=

−

4

3

Now that we have the slope, we need to find the y-intercept.

To find the y-intercept, we need to plug-in values of

x

and

y

that the line passes through

y

'

=

m

'

x

'

+

b

⇒

y

'

=

−

4

3

x

'

+

b

⇒

7

=

−

4

3

(

−

12

)

+

b

⇒

7

=

16

+

b

⇒

b

=

−

9

Therefore, the equation of the line is

y

=

−

4

3

x

−

9

4 0

3 years ago

9= 2/3 (x+12) plz help

avanturin [10]

Answer: x=3/2

Step-by-step explanation:

Multiply the parentheses by 2/3. 9=2/3x+8.

Multiply both sides by 3 . 27=2x+24

Move the term. When moved to the left side it changes from positive to a negative. -2x=24-27.

-2x=-3

Divide both sides by -2

x=3/2 (x=1 1/2, x=1.5)

5 0

3 years ago

A driver starts his parked car and within 7 seconds reaches a velocity of 75 m/s as he travels west. What is his acceleration?

Otrada [13]

Answer:

21

Step-by-step explanation:

jfnvjfog'nearg

5 0

3 years ago

Read 2 more answers

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

<u>Points (0,0) and (2,1):</u>

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

<u>Points (2,1) and (0,3):</u>

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

<u>Mass of the lamina that occupies region D is 4.</u>

<u />

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{y} = \int\limits^a_b {\int\limits^a_b {x.\rho(x,y)} \, dA }$

$M_{x}$ and $M_{y}$ are moments of the lamina about x-axis and y-axis, respectively.

Calculating moments:

For moment about x-axis:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{x} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2.y.(x+y)} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 {\int\limits^a_\frac{x}{2} {y.x+y^{2}} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{y^{2}x}{2}+\frac{y^{3}}{3})}\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{x(-x+3)^{2}}{2}+\frac{(-x+3)^{3}}{3} -\frac{x^{3}}{8}-\frac{x^{3}}{24} )}\, dx }$

$M_{x} = 2.(\frac{-9.x^{2}}{4}+9x)$

$M_{x} = 2.(\frac{-9.2^{2}}{4}+9.2)$

$M_{x} = 18$

Now to find the x-coordinate:

x = $\frac{M_{y}}{m}$

x = $\frac{63}{4}$

x = 15.75

For moment about the y-axis:

$M_{y} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2x.(x+y))} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {x^{2}+yx} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {y.x^{2}+x.{\frac{y^{2}}{2} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {x^{2}.(-x+3)+\frac{x.(-x+3)^{2}}{2} - {\frac{x^{3}}{2}-\frac{x^{3}}{8} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {\frac{-9x^3}{8}+\frac{9x}{2} } \,dx }$

$M_{y} = 2.({\frac{-9x^4}{32}+9x^{2})$

$M_{y} = 2.({\frac{-9.2^4}{32}+9.2^{2}-0)$

$M{y} =$ 63

To find y-coordinate:

y = $\frac{M_{x}}{m}$

y = $\frac{18}{4}$

y = 4.5

<u>Center mass coordinates for the lamina are (15.75,4.5)</u>

3 0

3 years ago

Please help me with the question

Damm [24]

Answer:

The right answer is Option 2:

$y+6 = -\frac{3}{4}(x-2)$

Step-by-step explanation:

Point-slope form of equation of a line is given by:

$y-y_1 = m(x-x_1)$

Here m is slope of the line and (x1,y1) is the point from which the line passes.

Given

Slope = m = -3/4

Point = (x1,y1) = (2,-6)

We simply have to put these value into the general form of equation of line in point-slope form

$y-(-6) = -\frac{3}{4}(x-2)\\y+6 = -\frac{3}{4}(x-2)$

Hence,

The right answer is Option 2:

$y+6 = -\frac{3}{4}(x-2)$

7 0

3 years ago