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brilliants [131]
3 years ago
7

Let T:V→W be a linear transformation from a vector space V into a vector space W. Prove that the range of T is a subspace of W.

Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

The range of T is a subspace of W.

Step-by-step explanation:

we have T:V→W

This is a linear transformation from V to W

we are required to prove that the range of T is a subspace of W

0 is a vector in range , u and v are two vectors in range T

T = T(V) = {T(v)║v∈V}

{w∈W≡v∈V such that T(w) = V}

T(0) = T(0ⁿ)

0 is  Zero in V

0ⁿ  is zero vector in W

T(V) is not an empty subset of W

w₁, w₂   ∈ T(v)

(v₁, v₂ ∈V)

from here we have that

T(v₁) = w₁

T(v₂) = w₂

t(v₁) + t(v₂) = w₁+w₂

v₁,v₂∈V

v₁+v₂∈V

with a scalar ∝

T(∝v) = ∝T(v)

such that

T(∝v) ∈T(v)

so we have that T(v) is a subspace of W. The range of T is a subspace of W.

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Subtitute 2x+y=7 and 3x-y=8
iogann1982 [59]

Answer:

x = 3 , y = 1

Step-by-step explanation:

2x + y = 7

3x + y = 8

solution

2x + y = 7-----------(1)

3x - y = 8------------(2)

from equation 1

2x + y = 7

y = 7 - 2x-------------(3)

substitute equation 3 into equation 2

3x - y = 8

3x - (7 - 2x) = 8

3x - 7 + 2x = 8

3x + 2x = 8 + 7

5x = 15

divide through by the coefficient of x

5x/5 = 15/5

x = 3

to find y

substitute x into equation 1

2x + y = 7

2(3) + y = 7

6 + y = 7

y = 7 - 6

y = 1

8 0
3 years ago
The radius of a circle measures 11 inches. A central angle of the circle measuring 5π9 radians cuts off a sector.
Elan Coil [88]

Answer:

605π/18

Step-by-step explanation:

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3 years ago
Consider the diagram. What is the length of segment AB?
Sloan [31]
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3 years ago
Read 2 more answers
Use the fraction strips to compare 2/4 and 5/8. use the drop-down menus to explain your comparison.
tia_tia [17]

Answer:

2

5

\dfrac{4}{5}

Step-by-step explanation:

We are given 2 fractional numbers:

1.\ \dfrac{2}4\\2.\ \dfrac{5}8

We have to use fraction strips to compare to the fractional numbers.

Let we are Comparing \frac{2}{4} with the length of x number of \frac{1}4 sections.

i.e.

\dfrac{2}{4}  = x \times \dfrac{1}{4}\\\Rightarrow x = \dfrac{2 \times 4}{4}\\\Rightarrow x = 2

Let we are Comparing \frac{5}{8} with the length of y number of \frac{1}8 sections.

i.e.

\dfrac{5}{8}  = y \times \dfrac{1}{8}\\\Rightarrow y = \dfrac{5 \times 8}{8}\\\Rightarrow y = 5

Now, let us have a look at 3rd part of question:

The sections of 2/4 is _____ the length of 5/8. Therefore, 2/4 < 5/8

Let the answer be z.

So, the equation becomes:

\dfrac{2}{4} = z \times \dfrac{5}{8}\\\Rightarrow z = \dfrac{2 \times 8}{4 \times 5}\\\Rightarrow z = \dfrac{2 \times 2}{5}\\\Rightarrow z = \dfrac{4}{5}

So, the answers are:

2

5

\dfrac{4}{5}

5 0
3 years ago
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I think it’s d. A percent is out of 100 so it’s 156/100
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