10+12p is the answer to that IXL problem
Answer:
1,2,3,2,2
Step-by-step explanation:
because standard form is ax
Answer:
Part 1 , not significant
Part II, significant
Step-by-step explanation:
Given that a heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 produce white-fruited plants while only 90 produce yellow-fruited plants

(Two tailed chi square test)
We assume H0 to be true and find out expected
If H0 is true expected would be 100 white and 100 yellow
Chi square = 
df = 1
p value = 0.152799
Since p value > 0.05 at 5% level we accept that the colours are equally likely
2)
Here observed are 1100 and 900
Expected 1000 & 1000
df = 1
Chi square = 
p value <0.0001
These results are here statistically significant.
This can solved using the cosine law which is:
c² = a² + b² - 2ab cos θ
Using the values given from the problem
6² = b² + b² - 2bb cos 112.62
And solving for b
36 = 2b² - 2b² cos 112.62
b = 3.6
The answer is the 3rd option.
Answer:

Step-by-step explanation:
We'll write the polynomial using only the roots required to simplify calculations. However, it states the final answer should not have a radical or complex number in. Therefore, we need to rid them:

Expanding this, we get:
.