In geometry, it would be always helpful to draw a diagram to illustrate the given problem.
This will also help to identify solutions, or discover missing information.
A figure is drawn for right triangle ABC, right-angled at B.
The altitude is drawn from the right-angled vertex B to the hypotenuse AC, dividing AC into two segments of length x and 4x.
We will be using the first two of the three metric relations of right triangles.
(1) BC^2=CD*CA (similarly, AB^2=AD*AC)
(2) BD^2=CD*DA
(3) CB*BA = BD*AC
Part (A)
From relation (2), we know that
BD^2=CD*DA
substitute values
8^2=x*(4x) => 4x^2=64, x^2=16, x=4
so CD=4, DA=4*4=16 (and AC=16+4=20)
Part (B)
Using relation (1)
AB^2=AD*AC
again, substitute values
AB^2=16*20=320=8^2*5
=>
AB
=sqrt(8^2*5)
=8sqrt(5)
=17.89 (approximately)
Answer:
15 is the middle number
Step-by-step explanation:
BECAUSE IF YOU COUNT FROM THE LEFT AND RIGHT AND WHICH NUMBER APPEARS IN THE MIDDLE IS YOUR MEDIAN
Answer: C
Step-by-step explanation: Consider a triangle with points A, B and C. You must create a perpendicular bisector of AB and then a perpendicular bisector of BC that crosses each other. Then you must label the center of that point D, and then using a compass tool, create a circle around the triangle.
Answer:
A right angle is neither Obtuse nor Acute
Step-by-step explanation: