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zhannawk [14.2K]

3 years ago

11

15/10 as a mixed number

1 answer:

Sauron [17]3 years ago

5 0

15/10

= 10/10 + 5/10

= 1 + 1/2

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What is the greatest whole number that rounds to 621860

konstantin123 [22]

621,864
Since the 4 is a smaller digit than a 5, the 6 in the tens place would stay the same while the 4 would become a 0.

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3 years ago

What is the sum of the rational expression below? 3x/x+2 + x/x+4

Darya [45]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

8 0

3 years ago

Answer these 3 questions ASAP pls..

matrenka [14]

That’s the answers hope this helps.

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3 years ago

SOLVE FOR J. <br><br> j+11.98≥-7.02 <br> (that is not a subtraction sign its a negative sign!!)

LiRa [457]

J>-19

Hope that helps

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3 years ago