Question

You are given that a wheel has a radius of 2 feet and a spin rate of 10 revolutions per minute. Describe how you would determine the linear velocity, in feet per minute, of a point on the edge of the wheel.

Answer 1

Answer:

Linear velocity of point on the edge of wheel having radius of 2 feet and spin rate of 10 revolution per minute is 125.71 feet per minute.

Solution:

Given that radius of wheel = 2 feet

There is a point on edge of the wheel .we need to determine linear velocity of that point.

Let’s first calculate distance covered by a point when 1 revolution of wheel is complete.

When one revolution is complete the distance traveled by a point on edge of the wheel will be equal to circumference of the wheel  

$=2 \pi \mathrm{r}=2 \mathrm{x}\left(\frac{22}{7}\right) \times 2=\frac{88}{7} \mathrm{feet}$

In one revolution, point covers distance of $\frac{88}{7}$ feet

So in 10 revolution, point covers distance of $\frac{88}{7} \times 10 = \frac{880}{7}$

Given that in a minute, wheel takes 10 revolution.

Which means in a minute , point covers $\frac{880}{7}$ feet that is $\frac{880}{7}$ feet per minute = 125.71 feet per minute

Hence linear velocity of point on the edge of wheel having radius of 2 feet and spin rate of 10 revolution per minute is 125.71 feet per minute.

Answer 2

Answer:

2.09.ft/min

Step-by-step explanation:

There is a formula for the linear velocity using rpm:

V = (2π)/60 * r * rpm

V = (2π)/60 * 2ft * 10 = 2.09ft/min