We can re-write the equation √(1-x) - 2y = 2 → - 2y = 2 - √(1-x)

→ 2y = - 2 + √(1-x) → and y = [ - 2 + √(1+x)]/2

Tis function "exists" as long as the radical is > or = to zero:
1+x > or = 0 → x>-1
{x ∈ R for x> =0}

5 0

3 years ago

In science class, jada uses a graduated cylinder with water in it to measure the volume of some marbles. After dropping in 4 mar

hammer [34]

Answer:

0.5

Step-by-step explanation:

4 marbles its at 10 and after dropping in 2 more its volume increased by one mL. and 1 divided by 2 equals 0.5.

3 0

3 years ago

Read 2 more answers

BRAINLIEST IF CORRECT

Lyrx [107]

Answer:

The price of the cereal boxes

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Suppose the probability of being in honors math is 0.30 and the probability of being in honors math and honors science is 0.20.

LekaFEV [45]

Answer:

20% probability of being in honors science if you are in honors math

Step-by-step explanation:

I am going to say that we have two events.

Event A: Being in honors in math. So P(A) = 0.3.

Event B: Being in honors in science. So P(B) = 0.2.

Since they are independent events, we can apply the conditional probability formula, which is:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probabilitty of event B happening given that A happened. We want to find this.

$P(A \cap B)$ is the probability of both events happening.

Since they are independent

$P(A \cap B) = P(A)P(B) = 0.3*0.2 = 0.06$

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.3} = 0.2$

20% probability of being in honors science if you are in honors math

8 0

3 years ago