Answer:
5.7
Step-by-step explanation:
Answer:
sorry don't know i just need points
GOOD LUCK
me and my friend are seeing who can get more points
Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.
Answer:
y + 1 = -1/2(x - 8)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Slope Formula: 
Point-Slope Form: y - y₁ = m(x - x₁)
- x₁ - x coordinate
- y₁ - y coordinate
- m - slope
Step-by-step explanation:
<u>Step 1: Define</u>
f(8) = -1 → Coordinate (8, -1)
f(6) = 0 → Coordinate (6, 0)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute [SF]:

- Add/Subtract:

- Simplify:

<u>Step 3: Write Function</u>
<em>Substitute into general form.</em>
- Point 1: y + 1 = -1/2(x - 8)
- Point 2: y = -1/2(x - 6)
I was stuck on the same thing in my class test. I ended up failing but if I get the answers to it I’ll totally send them to you