Answer:
a) 2a + 3c = $44.50
a + 2c + $25.50
b) $19
Step-by-step explanation:
Simultaneous equations. A = adult. C = children
2a + 3c = $44.50 (EQUATION 1)
a + 2c = $25.50 (EQUATION 2)
Now solve this using the method of elimination:
2a + 3c = $44.50 (EQUATION 1)
a + 2c = $25.50 (EQUATION 2)
Multiply equation 2 by 2 so that both equations have the same a coefficient.
2a + 4c = $51 (NEW EQUATION 2)
Now subtract equation 1 from equation 2:
2a - 2a + 4c - 3c = $51 - $44.50 (2a cancels out)
c = $6.50
Now substitute c into one of the equation, in this case, I'm using original equation 2.
a + 2($6.50) = $25.50
a + $13 = $25.50
a = $12.50
Total cost of one adult and child = $6.50 + $12.50
= $19
