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Anna [14]
3 years ago
7

The label on the car's antifreeze container claims to protect the car between −40°C and 140°C. To covert Celsius temperature to

Fahrenheit temperature, the formula is C=5/9(F-32). Write a compound inequality to determine the Fahrenheit temperature range at which the antifreeze protects the car.
Mathematics
1 answer:
telo118 [61]3 years ago
5 0

Answer:

-40

Step-by-step explanation:

We must convert the given temperatures from degrees Celsius to degrees Fahrenheit

The formula is:

C=\frac{5}{9}(F-32)

Where C is the temperature in degrees Celsius and F is the temperature in degrees Fahrenheit

Then we must replace the temperature in degrees Celsius and solve the equation for F

C*\frac{9}{5}=(F-32)

F=C*\frac{9}{5}+32

F=(-40)*\frac{9}{5}+32

F=-40\ \°F

F=(140)*\frac{9}{5}+32

F=284\ \°F

The Fahrenheit temperature range in which the antifreeze protects the car is:

-40

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Y is inversely proportional to x. If y= 400 when x =2 find y when x= 200
o-na [289]

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<u>Step-by-step explanation:</u>

Inversely proportional means xy = k, where k is the constant of proportionality

First, find k when x = 2 and y = 400 ----> 2(400) = k   --> 800 = k

Then, find y when x = 200 (knowing that k = 800)

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4 0
3 years ago
Please give me the correct answer ​
Ganezh [65]

Answer:

PQ = 5 units

QR = 8 units

Step-by-step explanation:

Given

P(-3, 3)

Q(2, 3)

R(2, -5)

To determine

The length of the segment PQ

The length of the segment QR

Determining the length of the segment PQ

From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.

so

P(-3, 3), Q(2, 3)

PQ = 2 - (-3)

PQ = 2+3

PQ = 5 units

Therefore, the length of the segment PQ = 5 units

Determining the length of the segment QR

Q(2, 3), R(2, -5)

(x₁, y₁) = (2, 3)

(x₂, y₂) = (2, -5)

The length between the segment QR is:

l=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

  =\sqrt{\left(2-2\right)^2+\left(-5-3\right)^2}

  =\sqrt{0+8^2}

  =\sqrt{8^2}

Apply radical rule: \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

  =8

Therefore, the length between the segment QR is: 8 units

Summary:

PQ = 5 units

QR = 8 units

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