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Ne4ueva [31]
3 years ago
13

At a math league contest there was 24 girls and ten boys what is the ratio of girls to boys

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
5 0
The ratio girls to boys is 12:5
Grace [21]3 years ago
4 0

Ansuswer:

Step-by-step explanation:

No. Of girls = 24

No. Of boy = 10

Ratio of girls to boy = 24:10

= 12:5

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The graph shows the relationship between the total cost and the number of gift cards that Raj bought for raffle prizes.
BabaBlast [244]

<u>The problem is as following:</u>

The graph shows the relationship between the total cost and the number of gift cards that Raj bought for raffle prizes. What would be the cost for 5 of the gift cards? $80, $90, $100 Or $110

===============================================================

<u>Solution</u>:

The points of the figure represents a straight line

The general form of the straight line is  ⇒ y = mx + c

where m is the slope and c is constant

let x ⇒ The number of gifts cards , y ⇒ Total cost (in $)

we will find m and c using the points (1,20) , (2,40)

The slope = m = \frac{y_{2} - y_{1}}{x_{2}-x_{1}} =\frac{40-20}{2-1} =\frac{20}{1}=20

∴ y = 20x + c

Substitute with the point (1,20) ⇒ y = 20 at x = 1

∴ 20 = 20 * 1 + c

∴ 20 = 20 + c

∴ c = 0

∴ The equation of the line ⇒⇒⇒ y = 20x

To find the cost for 5 of the gift cards substitute with x = 5

∴ y = 20 * 5 = 100

So, the cost for 5 of the gift cards = $100

<u>The correct answer is option 3 ⇒⇒⇒ $100</u>

6 0
3 years ago
Read 2 more answers
write the equation of the line in slope intercept form that is perpendicular to y=5x+4 and passes through the origin please help
Alja [10]

The answer would be

y=-1/5x

Hope this helps!

5 0
2 years ago
Carol used 1.8 gallons of paint for a barn.She used 1/5 of the remaining paint for a dog house. She had 2/7 paint left. How much
Lilit [14]
1 4/5 + 1/5 + 2/7 =

1 28/35 + 7/35 + 10/35 =

1 45/35 = 2 35/45 =

2.78 gallons rounded to the nearest hundredth
5 0
3 years ago
PLEASE HELP? IS THIS RIGHT OR NOT????
zepelin [54]
The answer is actually D. The limit on the left side is computing the derivative at x = a. The right side value of 7 tells us that f ' (a) = 7
3 0
3 years ago
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
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