Find the local maximum and two local minima of the graph of the following function.
1 answer:
Answer:
max is (3, 1) and min are (2, 0) and (4, 0)
Step-by-step explanation:
Since there is no bounds on this (not a closed interval), the only max and min we can find are local. The max and min points exist where the first derivative of the function is equal to 0. That means that we have to find the first derivative. That is:
If you factor this higher-degree polynomial (I used the Rational Root Theorem and then synthetic division), you find that the zeros of the derivative exist at the x values of
2, 3, 4
Therefore, f(2), f(3), and f(4) will either be max values or min values.
f(2) = 0 so the point is (2, 0)
f(3) = 1 so the point is (3, 1)
f(4) = 0 so the point is (4, 0)
As you can see, the max point is (3, 1)
the min points are (2, 0) and (4, 0)
You might be interested in
Answer:
4 cm
Step-by-step explanation:
The square root of 144 is 12 (12 x 12 = 144) so we know our sides of the square are 12 cm²
12 / 3 = 4
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The sides of the new square are 4 :)
Hope this helps and is correct, have a nice day! :D
Answer:
The expected number of appearance defects in a new car = 0.64
standard deviation = 0.93(approximately)
Step-by-step explanation:
Given -
7% had exactly three, 11% exactly two, and 21% only one defect in cars.
Let X be no of defects in a car
P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21
P(X=0 ) = 1 - .07 - .11 - .21 = 0.61
The expected number of appearance defects in a new car =
E(X) = =
= 0.64
= variation of E(X) =
=
= = 0.8704
standard deviation = =
= 0.93(approximately)