Answer:
1) (c)∠ G = 34°
2) (a) x = 33°
3) (d) The perpendicular segments are JM, KL, PQ AND NR.
Step-by-step explanation:
Here in the given questions:
1) p II r
⇒ ∠ G = 34° (ALTERNATE EXTERIOR ANGLES)
Hence, the measure of ∠ G = 34°
2) In the given triangle:
The measure of exterior angle is always the sum of interior opposite angles.
⇒ Here, x + 72° = 105°
or, x = 105° - 72° = 33° , or x = 33°
3) The given plane in the cube is JKPN
The segments which have J , K , P and N as their one vertex are perpendicular to the given plane.
Hence, the segments are JM, KL, PQ AND NR.
Answer:
first we need to substitute g(t) value in h(t) value and then evaluate the expression as follows :
h(g(t))=3(t-1)²+4(t-1).
by solving
h(g(t))=3(t²+1-2t)+4t-4
h(g(t))=3t²-2t-1 will.be the final answer
The equation for a trapezoid is A = a+b all over 2 times h
So, you would simply substitute.
A=15
B=12
H=8
15+12/2 (8)=
27/2 (8)=
13.5 (8)=
108.
Answer:
Exact answer is 0.00076232
Step-by-step explanation:
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