I think the answer would be 1/5
43 billion in scientific notation is:
4.3 × 10^10
Answer:
All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.
Step-by-step explanation:
Given,
Total distance covered = 6.2 miles,
Time taken = 34 minutes =
hours
( 1 hour = 60 minutes )
Since,
![Speed = \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
Thus, the speed of the runner = ![\frac{6.2}{\frac{34}{60}}](https://tex.z-dn.net/?f=%5Cfrac%7B6.2%7D%7B%5Cfrac%7B34%7D%7B60%7D%7D)
![=\frac{6.2\times 60}{34}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6.2%5Ctimes%2060%7D%7B34%7D)
![=\frac{372}{34}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B372%7D%7B34%7D)
= 10.9411764706
≈ 11 miles per hour
Thus, the average speed of the runner is 11 miles per hour ( approx )
By MVT,
The speed was exactly 10 mi/hr at least twice in the race.
By intermediate value theorem,
All speed from 0 mi/h and 11 mi/h were reached because the initial and final speed was 0 mi/h the speed of 10 mi/hr was reached at least twice in the race.