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Vanyuwa [196]
3 years ago
14

How to solve -x^2-2x=5?

Mathematics
1 answer:
anastassius [24]3 years ago
6 0
-x^2 - 2x - 5=0
-(x^2 + 2x + 1) -4=0
(x +1)^2= -4
=> Impossible. There is no x
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Vincent works 8 hours a day for 5 days. How much does he earn at the rate of $.97 per hour?
Tresset [83]

Answer:

$38.8

Step-by-step explanation:

First, find how much money he gets paid in a day. Multiply 8 x .97, which equals $7.76. Then, multiply $7.76 x 5 to see how much he gets paid in 5 days. $7.76 x 5= $38.8

Hope this helps!

6 0
3 years ago
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Draw two lines with a slope of 1 / 2. What do you notice about the lines?
patriot [66]

Answer:

The lines would be parallel.

Step-by-step explanation:

lines with the same slope are parallel.

6 0
3 years ago
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The two-column proof below describes the statement and reason for proving that corresponding angles are congruent.
noname [10]
Step 6 wants us to show two angles which are also two interior angles that are located on the same side.

Interior angles are angles that are INSIDE the parallel lines.

On the diagram given, there are two pairs of interior angles that are on the same side:

Angle VQT and angle ZRS
Angle UQT and angle WRS

Two interior angles on the same sides add up to 180°

The missing statement that would fit statement in Step 6 is:
m∠VQT + m∠ZRS = 180°

Answer: Second option

3 0
3 years ago
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Solve with interval notation Solve: 5 | x − 2 | + 4 > 8
Gnesinka [82]

Answer:

x<6/5, x>14/5

Step-by-step explanation:

Steps

$5\left|x-2\right|+4>8$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$5\left|x-2\right|+4-4>8-4$

$\mathrm{Simplify}$

$5\left|x-2\right|>4$

$\mathrm{Divide\:both\:sides\:by\:}5$

$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$

$\mathrm{Simplify}$

$\left|x-2\right|>\frac{4}{5}$

$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$

$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$

Show Steps

$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$

Show Steps

$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$

$\mathrm{Combine\:the\:intervals}$

$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$

5 0
3 years ago
Please help!! I’ve been struggling for days.
Tomtit [17]

Answer:

y=-1/4x-6

Step-by-step explanation:

y intercept is -6 and slope is -1/4

point slope is y-y1=m(x-x1)

you can use and point. i am using (0,-6)

y--6=-1/4(x-0)

y+6=-1/4x

-6 -6

y=-1/4x-6

7 0
3 years ago
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