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Vanyuwa [196]
3 years ago
14

How to solve -x^2-2x=5?

Mathematics
1 answer:
anastassius [24]3 years ago
6 0
-x^2 - 2x - 5=0
-(x^2 + 2x + 1) -4=0
(x +1)^2= -4
=> Impossible. There is no x
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URGENT! Please help me with this question!!!!!
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Answer:

\boxed{GJ = 76 \ degrees}

Step-by-step explanation:

According to Angles of intersecting chords theorem:

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Answer:

Step-by-step explanation:

The set {1,2,3,4,5,6} has a total of 6! permutations

a. Of those 6! permutations, 5!=120 begin with 1. So first 120 numbers would contain 1 as the unit digit.

b. The next 120, including the 124th, would begin with  '2'  

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d. Of these 4! permutations beginning with 21, there are 3!=6 including the 124th permutation which have third digit 3

e. Among these 3! permutations beginning with 213, there are 2 numbers with the fourth digit =4 (121th & 122th), 2 with fourth digit 5 (numbers 123 & 124) and 2 with fourth digit 6 (numbers 125 and 126).

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Similarly reversing the above procedure we can determine the position of 321546 to be 267th on the list.

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2 years ago
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