Answer:
1. Option A
2. Option B
Step-by-step explanation:
I would like to elaborate on the answer to the second question, since the first answer is actually option a. Why? The question asks for a parametric equation, not set, so it would be choice a.
2. x=3t + 5 - isolate t
t=(x-5)/3 - substitute into the second equation
y = [(x-5)/3]^2 - 1
your solution is option b
Doesn’t make sense.. how much can fit into one packet
Answer:
b = -57/10
Step-by-step explanation:
Let's first distribute everything out:
-8(1 + 5b) = -8 * 1 + (-8) * 5b = -8 - 40b
2(86 - 1) = 2 * 85 = 170
So, we have:
-8 - 40b - 170 = 50
-40b - 178 = 50
-40b = 50 + 178 = 228
b = -228/40 = -57/10
Thus, the answer is b = -57/10.
Hope this helps!
Well 40 times 6 is 240 which means that you don't have to round.
Ln ( a^(-4) / b^1 c^1 ) =
= ln a ^(-4) - ( ln b + ln c ) =
= - 4 ln a - ln b - ln c =
= - 4 * 2 - 3 - 5 =
= - 8 - 3 - 5 = - 16
